[해커랭크] Library Fine

[해커랭크] Library Fine

 

https://www.hackerrank.com/challenges/library-fine/problem?isFullScreen=true

Library Fine | HackerRank

 

Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:

1. If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
2. If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, .
3. If the book is returned after the expected return month but still within the same calendar year as the expected return date, the .
4. If the book is returned after the calendar year in which it was expected, there is a fixed fine of .

Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .

Example

The first values are the return date and the second are the due date. The years are the same and the months are the same. The book is  days late. Return .

Function Description

Complete the libraryFine function in the editor below.

libraryFine has the following parameter(s):

• d1, m1, y1: returned date day, month and year, each an integer
• d2, m2, y2: due date day, month and year, each an integer

Returns

• int: the amount of the fine or  if there is none

Input Format

The first line contains  space-separated integers, , denoting the respective , , and  on which the book was returned.
The second line contains  space-separated integers, , denoting the respective , , and  on which the book was due to be returned.

Constraints

•  
•  
•  
•  

Sample Input

9 6 2015
6 6 2015

Sample Output

45

Explanation

Given the following dates:
Returned: 
Due: 

Because , we know it is less than a year late.
Because , we know it's less than a month late.
Because , we know that it was returned late (but still within the same month and year).

Per the library's fee structure, we know that our fine will be . We then print the result of  as our output.

 

 

 

 

풀이

반납을 일찍한 경우만 잘 처리하면 나머지는 단순 계산입니다.

 

 

 

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.function.*;

import java.util.regex.*;

import java.util.stream.*;

import static java.util.stream.Collectors.joining;

import static java.util.stream.Collectors.toList;

class Result {

    /*

     * Complete the 'libraryFine' function below.

     *

     * The function is expected to return an INTEGER.

     * The function accepts following parameters:

     *  1. INTEGER d1

     *  2. INTEGER m1

     *  3. INTEGER y1

     *  4. INTEGER d2

     *  5. INTEGER m2

     *  6. INTEGER y2

     */

    public static int libraryFine(int d1, int m1, int y1, int d2, int m2, int y2) {

    // Write your code here

   

        int fee = 0;

   

        if ( (y1<y2) || (y1==y2 && m1<m2) || (y1==y2 && m1==m2 && d1<=d2)){

            fee = 0;

        }

        else if (y1==y2 && m1==m2){

            fee += ((d1 - d2)*15);

        }

        else if(y1==y2){

            fee += ((m1-m2)*500);

        }

        else{

            fee += 10000;

        }

   

        return fee;

    }

}

public class Solution {

    public static void main(String[] args) throws IOException {

        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        String[] firstMultipleInput = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");

        int d1 = Integer.parseInt(firstMultipleInput[0]);

        int m1 = Integer.parseInt(firstMultipleInput[1]);

        int y1 = Integer.parseInt(firstMultipleInput[2]);

        String[] secondMultipleInput = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");

        int d2 = Integer.parseInt(secondMultipleInput[0]);

        int m2 = Integer.parseInt(secondMultipleInput[1]);

        int y2 = Integer.parseInt(secondMultipleInput[2]);

        int result = Result.libraryFine(d1, m1, y1, d2, m2, y2);

        bufferedWriter.write(String.valueOf(result));

        bufferedWriter.newLine();

        bufferedReader.close();

        bufferedWriter.close();

    }

}